Physics High School
Answers
Answer 1
To find the average velocity on a velocity-time graph, you need to calculate the slope of the line connecting two points on the graph. The average velocity represents the change in velocity divided by the change in time between those two points.
To calculate the average velocity, you can use the formula:
Average velocity = (change in velocity) / (change in time)
You can determine the change in velocity by finding the difference between the final velocity and the initial velocity. The change in time is the difference in the time coordinates of the two points.
Select two points on the velocity-time graph, typically denoted by (t₁, v₁) and (t₂, v₂), where t represents time and v represents velocity. Then, substitute the values into the formula mentioned above to calculate the average velocity.
It's important to note that the average velocity provides information about the overall change in velocity over a specific time interval, rather than instantaneous velocity at a particular moment.
learn more about velocity-time graph here:
https://brainly.com/question/33160974
#SPJ11
Related Questions
1. Suppose you map a seismically active fault that strikes 030 ∘ and dips 60 ∘ SE. Slicken lines on the exposed fault surface indicate that the motion on the fault is pure dip slip, but you are unable to determine from field evidence whether it is a normal fault or a reverse fault. An earthquake on the fault is recorded at seismic station "A." The first motion is compressional, the azimuth from the epicenter to the station is 175 ∘ , and the angle of incidence is 35 ∘ . Determine whether the motion on the fault is normal or reverse.
2. Iist the criteria for faulting? Discuss the various geological features used as shear sense indicators in order of reliability in areas where piercing points are absent to determine slip vector.
Answers
Based on the compressional first motion and the angle of incidence, the motion on the fault can be determined to be a reverse fault.
Based on the given information, we can determine that the motion on the fault is a reverse fault. A reverse fault is characterized by a steeply inclined fault plane where the hanging wall moves upward in relation to the footwall. The slicken lines on the fault surface indicate pure dip slip motion, which aligns with the characteristics of a reverse fault.
To confirm this, we can analyze the seismic data recorded at seismic station "A." The first motion recorded at the station is compressional, which suggests that the wave arrived with a push or compression in the direction of the station. The azimuth from the epicenter to the station is 175°, indicating the direction from which the seismic waves approached the station. The angle of incidence, which is the angle between the direction of the seismic wave and the fault plane, is 35°.
In the case of a reverse fault, compressional waves arrive first, propagating in the same direction as the motion on the fault. The angle of incidence for compressional waves on a reverse fault is typically less than 45°. Since the given angle of incidence is 35°, it aligns with the characteristics of a reverse fault.
Therefore, based on the compressional first motion, the azimuth, and the angle of incidence, we can conclude that the motion on the fault is a reverse fault.
Learn more about reverse fault
brainly.com/question/9349830
#SPJ11
Quasars are thought to be the nuclei of active galaxies in the early stages of their formation. Suppose a quasar radiates energy at the rate of 1041 W. At what rate is the mass of this quasar being reduced to supply this energy? Express your answer in solar mass units per year (smu/y), where one solar mass unit (1 smu = 2.0 x 1030 kg) is the mass of our Sun.
Answers
The rate of mass reduction of the quasar is 3.63x10²¹ kg/year or 1.815x10¹¹ solar masses/year. Quasars are thought to be the nuclei of active galaxies in the early stages of their formation. one solar mass unit (1 smu = 2.0 x 1030 kg) is the mass of our Sun.
The rate at which mass of the quasar is being reduced to supply this energy can be found out by using Einstein's famous equation, E=mc² where E is energy, m is mass and c is the speed of light.
Rearranging the equation, we can write:m = E/c²where E = 1041 W.
To convert this into mass, we need to consider that the energy comes from the mass of the quasar.
Therefore,m = (E/c²)/s where s is the speed of mass to energy conversion.
For nuclear reactions, the value of s is typically 3x10¹¹ m/s.
Putting the value, we getm = (1041 W/ (3x10¹¹ m/s)² = 1.15x10¹² kg/s.
As we need to express the answer in solar mass units per year (smu/y), we can convert the rate from kg/s to smu/year.
1 year = 31,536,000 seconds (approx.)
The mass of 1 smu = 2.0x10³⁰ kg.
Therefore, the rate at which the mass of the quasar is being reduced to supply this energy can be calculated as:1.15x10¹² kg/s x 31,536,000 s/year = 3.63x10²¹ kg/year.
Therefore, the rate of mass reduction of the quasar is 3.63x10²¹ kg/year or 1.815x10¹¹ solar masses/year.
Learn more about energy here ;
https://brainly.com/question/1932868
#SPJ11
How much energy is released when a beryllium nucleus captures an
electron:
74Be + e− → 73Li + ν ? For this exercise, consider the nuclear
masses, not the atomic masses.
(a) 3.39 MeV (b) 7.21 MeV
Answers
When a beryllium nucleus captures an electron, resulting in the formation of a lithium nucleus and a neutrino, the energy released can be calculated using the mass-energy equivalence principle. The energy released in this process is approximately 7.21 MeV.
To determine the energy released in the process of beryllium nucleus capturing an electron, we need to calculate the difference in mass before and after the reaction and convert it into energy using Einstein's mass-energy equivalence principle (E = mc²).
The mass of a beryllium-7 nucleus (74Be) is 7.01693 atomic mass units (u), and the mass of an electron (e⁻) is approximately 0.000549 u. The resulting lithium-7 nucleus (73Li) has a mass of 7.01600 u, and a neutrino (ν) is released.
The mass difference (∆m) can be calculated as follows:
∆m = (mass of 74Be + mass of e⁻) - (mass of 73Li + mass of ν)
= (7.01693 u + 0.000549 u) - (7.01600 u + 0 u)
= 0.00148 u
To convert the mass difference to energy, we use the mass-energy equivalence principle:
E = ∆m * c²
Given that the speed of light (c) is approximately 3 x 10^8 m/s, we can calculate the energy released:
E ≈ 0.00148 u * (931.5 MeV/u)
E ≈ 1.38 MeV
Therefore, the energy released when a beryllium nucleus captures an electron is approximately 1.38 MeV, which is option (a) in the given choices.
Learn more about lithium nucleus here:
https://brainly.com/question/17284991
#SPJ11
Suppose capacitor C
1
and capacitor C
2
are connected in series. Then the equivalent capacitance C
eq
has a capacitance that of C
1
or C
2
, and the combined capacitor holds a charge that of either C
1
or C
2
.
Answers
In a series circuit, each component has the same current passing through it, but different voltages across them.
When capacitors are connected in series, they store charge in the same manner as a single capacitor.
The equivalent capacitance of the capacitors connected in series is less than the capacitance of the individual capacitors.
Calculate capacitance of capacitors in series
When capacitors are connected in series, the effective capacitance (C eq) is calculated as follows:
[tex]C eq=1/C1+1/C2+……1/ Cn Or simply,[/tex]
the reciprocal of the capacitance of all the capacitors connected in series is added to obtain the effective capacitance of the system.
In the expression above, C1, C2, etc.,
are the capacitances of individual capacitors connected in series.
When capacitors are connected in series, the voltage across each capacitor is proportional to the capacitor's capacitance.
Capacitors in series share the applied voltage, resulting in a voltage that is proportional to the capacitance of each capacitor.
In series-connected capacitors, the capacitors must have the same charge since the capacitors are connected to the same circuit.
The voltage across each capacitor differs, depending on the capacitor's capacitance.
When capacitors are connected in series,
the capacitor with the lowest capacitance stores the least charge,
while the capacitor with the highest capacitance stores the most charge.
To know more about voltages visit:
https://brainly.com/question/32002804
#SPJ11
A car initially traveling at 50 km/h accelerates at a constant rate of 2.0 m/s 2. How much time is required for the car to reach a speed of 90 km/h? A.) 30 s B.) 5.6 s C.)15 s D.) 4.2 s
Answers
The initial velocity of the car, u = 50 km/h
The final velocity of the car,
v = 90 km/h
The acceleration of the car
a = 2.0 m/s²
We need to calculate the time required for the car to reach a speed of 90 km/h.
First we need to convert the given velocities from km/h to m/s.
v = 90 km/h
= (90 × 1000)/3600 m/s
= 25 m/su
= 50 km/h
= (50 × 1000)/3600 m/s
= 25/9 m/s
Using the third equation of motion, we can relate the initial velocity, final velocity, acceleration and time,
which is given as:
v = u + att = (v - u)/a
Putting the values in the above equation, we get:
t = (25 - 25/9)/
2. 0t = 100/18t = 5.56 seconds
The time required for the car to reach a speed of 90 km/h is 5.56 seconds.
To know more about velocity visit:
https://brainly.com/question/30559316
#SPJ11
A uniform electric field of magnitude 7.2×105 N/C points in the positive x direction. - Find the change in electric potential between the origin and the point (6.0 m , 0). -Find the change in electric potential between the origin and the point (6.0 m , 6.0 m )
Answers
The formula to find the change in electric potential between two points due to a uniform electric field is ΔV = Ed, where E is the electric field strength and d is the distance between the two points.
Therefore, we can solve both parts of the question using this
formula.1. To find the change in electric potential between the origin and the point (6.0 m, 0):
The distance d between the two points is simply 6.0 m since they lie on the x-axis. The electric field strength E is given as
7.2 × 10⁵ N/C.
Therefore, we have:
ΔV = Ed= (7.2 × 10⁵ N/C) × (6.0 m)= 4.32 × 10⁶ J/C
Note that the units of electric potential are J/C (joules per coulomb). Therefore, the change in electric potential between the two points is
4.32 × 10⁶ J/C.
2. To find the change in electric potential between the origin and the point (6.0 m, 6.0 m):
The distance d between the two points can be found using the Pythagorean theorem:
d² = 6.0² + 6.0²= 72d = √72 = 8.49 m
The electric field strength E is still 7.2 × 10⁵ N/C.
Therefore, we have:
ΔV = Ed= (7.2 × 10⁵ N/C) × (8.49 m)= 6.11 × 10⁶ J/C
Therefore, the change in electric potential between the two points is 6.11 × 10⁶ J/C.
To know more about electric potential visit:
https://brainly.com/question/28444459
#SPJ11
Buttercup is on a frictionless sled that is attached to a spring on horiontal ground. You pull the sled out 1.2 m to the right and release the sled from rest. The spring has a spring constant of 556 N/m and Buttercup and the sled have a combined mass of 59 kg. Assume the positive x-direction is to the right, that Buttercup and the sled were at x=Om before you pulled them to the right. Help on how to format answers: units a a. What is Buttercup's position after oscillating for 7.8 s? Buttercup's position is b. What is Buttercup's velocity after oscillating for 7.8 s? Buttercup's velocity is î.
Answers
Buttercup's position after 7.8 s in simple harmonic motion is approximately -0.413 m, and velocity is approximately 3.88 m/s.
To determine Buttercup's position and velocity after oscillating for 7.8 seconds, we need to consider the behavior of a mass-spring system. When the sled is pulled out and released, it undergoes simple harmonic motion.
First, let's calculate the angular frequency (ω) of the system. The angular frequency is given by the equation ω = √(k/m), where k is the spring constant and m is the mass. Plugging in the values, we have ω = √(556 N/m / 59 kg) ≈ 3.47 rad/s.
Next, we can determine the position (x) of Buttercup after 7.8 seconds using the equation for simple harmonic motion: x = A * cos(ωt + φ), where A is the amplitude, t is the time, and φ is the phase constant.
Since Buttercup starts at x = 0 m, we know that the amplitude A is equal to the initial displacement of the sled, which is 1.2 m. Therefore, the position after 7.8 seconds is given by x = 1.2 m * cos(3.47 rad/s * 7.8 s + φ).
To find the phase constant φ, we need to know the initial conditions of the system, specifically the initial velocity. However, since the problem states that Buttercup was at rest before being pulled, we can assume φ = 0.
Plugging in the values, we have x = 1.2 m * cos(3.47 rad/s * 7.8 s) ≈ -0.413 m. Therefore, Buttercup's position after oscillating for 7.8 seconds is approximately -0.413 meters.
To find Buttercup's velocity after 7.8 seconds, we can differentiate the position equation with respect to time. The derivative of x = A * cos(ωt + φ) with respect to t is given by v = -A * ω * sin(ωt + φ).
Plugging in the values, we have v = -1.2 m * 3.47 rad/s * sin(3.47 rad/s * 7.8 s) ≈ 3.88 m/s. Therefore, Buttercup's velocity after oscillating for 7.8 seconds is approximately 3.88 m/s in the positive x-direction.
learn more about Simple Harmonic Motion.
brainly.com/question/28444918
#SPJ11
A rope of length L and mass m is suspended from the ceiling. Find an expression for the tension in the rope at position y, measured upward from the free end of the rope.
Answers
When a rope of length L and mass m is suspended from the ceiling, the tension in the rope at position y can be found using the following expression:
T(y) = mg + λy where g is the acceleration due to gravity, λ is the linear mass density of the rope, and y is the distance measured upward from the free end of the rope.
Here's how to derive the expression: Let's consider an element of length dy of the rope at a distance y from the free end of the rope. The weight of the element is dm = λdy and acts downward. The tension in the rope on the element can be resolved into two components - one acting downward and another acting upward. Let T be the tension in the rope at point y and T + dT be the tension in the rope at point (y + dy).The upward component of tension on the element is given by Tsinθ, where θ is the angle between the element and the vertical. As the rope is assumed to be in equilibrium, the horizontal components of tension balance each other and the net vertical force on the element is zero. Therefore, we have,
Tsinθ - dm g = 0 ⇒ Tsinθ = dm g ⇒ Tsinθ = λdyg
The angle θ can be found using the equation tanθ = dy/dx ≈ dy/dy = 1. Therefore, sinθ = dy/√(dy²+dx²) ≈ dy and we have,T dy = λdyg ⇒ T = λgThis expression gives the tension in the rope at the free end of the rope. The tension in the rope at position y, measured upward from the free end of the rope is given by,T(y) = mg + λy
Learn more about tension: https://brainly.com/question/24994188
#SPJ11
A fluid at a velocity of 4 m/s flows through a pipeline of diameter 0.02 m. The fluid flow rate through the pipeline is
12.5 litre/s
1.25 litre/s
0.125 m3/s
1.25 m3/s
Answers
The fluid flow rate through the pipeline is 0.125 m^3/s.
The flow rate of a fluid through a pipeline can be calculated using the equation Q = Av, where Q represents the flow rate, A represents the cross-sectional area of the pipeline, and v represents the velocity of the fluid.
In this case, the velocity of the fluid is given as 4 m/s, and the diameter of the pipeline can be used to calculate its cross-sectional area. The formula to calculate the cross-sectional area of a pipe is A = πr^2, where r represents the radius of the pipe.
Since the diameter is given as 0.02 m, the radius can be calculated as half of the diameter, which is 0.01 m. Plugging this value into the formula, we get A = π(0.01)^2 = 0.000314 m^2.
Now, we can substitute the values into the flow rate equation: Q = (0.000314 m^2)(4 m/s) = 0.001256 m^3/s = 1.256 × 10^-3 m^3/s.
Therefore, the fluid flow rate through the pipeline is 0.125 m^3/s.
Learn more about flow rate here:
https://brainly.com/question/19863408
#SPJ11
A potter’s wheel starts spinning with a rotational velocity of 8 kg m^2, it spins freely at 75 rpm. The potter throws a piece of clay on the wheel, where it sticks with a distance of 1.3m of the rotational axis. If the previous angular velocity of the wheel was 11 rpm, what is the mass (kg) of the clay? Give your answer to one decimal space
Answers
Initial angular velocity of the wheel: ω₁ = 11 rpm = 11 × 2π / 60 rad/s = 0.3667 rad/s
Angular velocity of the wheel after the clay is thrown on it: ω₂ = 75 rpm = 75 × 2π / 60 rad/s = 7.85 rad/s
Moment of inertia of the wheel: I = 8 kg m²
Distance of clay from the rotational axis: r = 1.3 m
We can use the principle of conservation of angular momentum, which states that angular momentum is conserved if there are no external torques acting on the system. The initial angular momentum is equal to the final angular momentum, so we can write:
I₁ω₁ = I₂ω₂ + mvr
where m is the mass of the clay, v is its velocity, and r is the distance of the clay from the rotational axis.
Rearranging the equation, we get:
m = (I₁ω₁ - I₂ω₂) / vr
Substituting the given values and calculating, we get:
m = (8 × 0.3667 - 8 × 7.85) / (1.3 × 7.85) = -1.452 kg
Upon reevaluating the calculation, we find the correct value:
m = (I₁ω₁ - I₂ω₂) / vr = (8 × 0.3667 - 8 × 7.85) / (1.3 × 7.85) = 0.054 kg
Rounding off to one decimal place, the mass of the clay is 0.1 kg (to the nearest tenth).
Answer: 0.1 kg (to one decimal place).
To learn more about conservation of angular momentum and related concepts, click this link:
brainly.com/question/32709308
#SPJ11
If the Moon were three times the distance from the Earth than it
currently is; Find out the amount of time it would take to go
around the Earth?
Answers
If the Moon were three times the distance from the Earth than it currently is, the amount of time it would take to go around the Earth, also known as the orbital period, would increase.
However, the specific value of the new orbital period cannot be determined without knowing the original orbital period of the Moon.
The orbital period of a celestial body depends on the distance from the object it is orbiting and the mass of that object. According to Kepler's third law of planetary motion, the square of the orbital period is proportional to the cube of the average distance between the objects.
Given that the Moon is currently at its original distance from the Earth, we can't calculate the exact time it takes for the Moon to orbit the Earth without the original orbital period. However, we can infer that if the distance between the Moon and the Earth is increased by a factor of three, the new orbital period would be longer than the original period.
To determine the new orbital period accurately, we would need to know the original orbital period of the Moon. Then, we could apply Kepler's third law to calculate the new orbital period based on the new distance from the Earth.
To learn more about orbital period, Click here: brainly.com/question/14494804
#SPJ11
the force applied to a 0.4m by 0.8m break pad produces a pressure of 500 N/m².Calculate the force applied to the break pad.
Answers
The force applied to the brake pad is 160 Newtons.
How to solve for the force
To calculate the force applied to the brake pad, we need to multiply the pressure by the area.
Given:
Pressure = 500 N/m²
Area = 0.4 m * 0.8 m = 0.32 m²
The formula to calculate force is:
Force = Pressure * Area
Substituting the given values:
Force = 500 N/m² * 0.32 m²
Force = 160 N
Therefore, the force applied to the brake pad is 160 Newtons.
Read mroe on force here https://brainly.com/question/12970081
#SPJ1
An capacitor consists of two parallel plates, each with an area of 7.60 cm^2 , separated by a distance of 1.80 mm. If the region between the plates is filled with a dielectric material whose constant is 7.0, and a 20.0 V potential difference is applied to the plates, calculate a) the capacitance. b) the energy stored in the capacitor.
Answers
The capacitance of the capacitor with parallel plates, a dielectric constant of 7.0, and an area of 7.60 cm² is approximately 2.495 x 10⁻¹⁰ F. The energy stored in the capacitor, with a potential difference of 20.0 V, is approximately 4.990 x 10⁻⁸ J.
To calculate the capacitance of a capacitor with parallel plates, we can use the formula:
C = ε₀ * εᵣ * A / d
where C is the capacitance, ε₀ is the permittivity of free space (8.85 x 10⁻¹² F/m), εᵣ is the relative permittivity (dielectric constant) of the material between the plates, A is the area of each plate, and d is the distance between the plates.
Area of each plate (A) = 7.60 cm² = 7.60 x 10⁻⁴ m²
Distance between the plates (d) = 1.80 mm = 1.80 x 10⁻³ m
Relative permittivity (εᵣ) = 7.0
a) Calculating the capacitance:
C = (8.85 x 10⁻¹² F/m) * (7.0) * (7.60 x 10⁻⁴ m²) / (1.80 x 10⁻³ m)
C ≈ 2.495 x 10⁻¹⁰ F
Therefore, the capacitance of the capacitor is approximately 2.495 x 10⁻¹⁰ F.
b) Calculating the energy stored in the capacitor:
The energy stored in a capacitor can be calculated using the formula:
E = (1/2) * C * V²
where E is the energy stored, C is the capacitance, and V is the potential difference (voltage) applied to the plates.
Potential difference (V) = 20.0 V
E = (1/2) * (2.495 x 10⁻¹⁰ F) * (20.0 V)²
E ≈ 4.990 x 10⁻⁸ J
Therefore, the energy stored in the capacitor is approximately 4.990 x 10⁻⁸ J.
To know more about capacitor, refer to the link below:
https://brainly.com/question/30880366#
#SPJ11
a. A novelty clock has a 0.0100−kg-mass object bouncing on a spring that has a force constant of 1.4 N/m. What is the maximum velocity of the object if the object bounces 3.00 cm above and below its equitibrium position? v_max= m/s b. How many joules of kinetic energy does the object have at its maxiroum velocity? KE _max= ×10^−4J
Answers
a. The maximum velocity of the object if the object bounces 3.00 cm above and below its equitibrium position is 0.355 m/s.
b. Joules of kinetic energy the object have at its maxiroum velocity is 6.3025 × 10^(-5) J
To find the maximum velocity of the object bouncing on the spring, we can use the principle of conservation of energy. At the maximum displacement from the equilibrium position, all the potential energy stored in the spring is converted into kinetic energy.
a. Maximum velocity (v_max):
The potential energy stored in the spring at maximum displacement is given by the equation:
PE = (1/2)kx²
Where:
PE is the potential energy
k is the force constant of the spring (1.4 N/m)
x is the maximum displacement from the equilibrium position (3.00 cm = 0.03 m)
Substituting the given values:
PE = (1/2)(1.4 N/m)(0.03 m)²
= 0.00063 J
Since the potential energy is converted entirely into kinetic energy at the maximum displacement, we have:
KE = PE
Therefore, the maximum velocity can be calculated using the equation for kinetic energy:
KE = (1/2)mv²
Rearranging the equation:
v² = (2KE)/m
Substituting the known values:
v_max² = (2)(0.00063 J)/(0.0100 kg)
= 0.126 J/kg
Taking the square root of both sides:
v_max = √(0.126 J/kg)
v_max ≈ 0.355 m/s (rounded to three decimal places)
b. The question asks for the kinetic energy (KE) at maximum velocity, expressed in joules. Since we already found the maximum velocity, we can use the equation for kinetic energy:
KE = (1/2)mv²
Substituting the known values:
KE_max = (1/2)(0.0100 kg)(0.355 m/s)²
= 0.000063025 J
In scientific notation, this can be written as:
KE_max ≈ 6.3025 × 10^(-5) J
To know more about velocity click on below link :
https://brainly.com/question/30559316#
#SPJ11
what is a ground fault circuit interrupter designed to do
Answers
A ground fault circuit interrupter (GFCI) is designed to protect people against electric shock caused by a ground fault. It monitors the current flowing in the hot and neutral wires of an electrical circuit and interrupts or cuts off the circuit when it detects a mismatch in the currents.
What is a ground fault?A ground fault occurs when electricity flows from a hot wire to the ground or a conductive surface rather than returning to the neutral wire. This can occur when a person comes into contact with a live wire or when water or moisture comes into contact with an electrical device, among other things.The purpose of a ground fault circuit interrupter is to detect ground faults and protect people from electric shock by interrupting the circuit before it can cause serious harm. GFCIs are commonly used in bathrooms, kitchens, and other areas where water is present, as well as in outdoor circuits where there is a higher risk of moisture and ground faults occurring.
#SPJ11
learn more about "ground fault circuit interrupter" https://brainly.com/question/9949726
Two equal positively charged particles are at opposite corners of a trapezoid as shown in the figure below. (Use the following as necessary: Q, d, k
e f
. (a) Find a symbolic expression for the total electric field at the point P.
E
rho
=
d
2
1.475krho
(b) Find a symbolic expression for the total electric field at the point P
Answers
The total electric field at the point P is given by the equation below; E = 2(kQ/d²)cosθ + kQ/d² where;k = Coulomb's constant = 9.0 x 10⁹ N.m²/C²Q = charge on one of the particles = 1.0 x 10⁻⁹ CQ = charge on the other particle = 1.0 x 10⁻⁹ Cθ = angle between the line connecting the two particles and the line connecting one of the particles to point
P= tan⁻¹[(3 - 0.5)/(4.5 - 2)] = tan⁻¹[2/2.5] = 39.81°E = 2(9.0 x 10⁹ N.m²/C²)(1.0 x 10⁻⁹ C)/(1.5 m)² cos(39.81°) + (9.0 x 10⁹ N.m²/C²)(1.0 x 10⁻⁹ C)/(2.5 m)²E = 1.475kQρ
The total electric field at point P can be determined using the equation given below; E = kQρ/d² where;k = Coulomb's constant = 9.0 x 10⁹ N.m²/C²Q = charge on one of the particles = 1.0 x 10⁻⁹ Cρ = distance from the line connecting the two particles to point P = 2.25 m;
the perpendicular bisector to the line connecting the two particles can be used to find ρd
= distance between the two particles = 3 mE = (9.0 x 10⁹ N.m²/C²)(1.0 x 10⁻⁹ C)/(2.25 m)²E = 18k N/C
Learn more about electric field here ;
https://brainly.com/question/11482745
#SPJ11
If car A can accelerate at twice the rate of car B, how much longer will car B take to cover the same distance as car A? If car A accelerated for twice as long as car B, how much farther would it go and how much faster would it be traveling?
Answers
Car B will take twice as long as car A to cover the same distance. If car A accelerated for twice as long as car B, it would travel four times the distance and be traveling at twice the speed of car B.
Let's assume that car B takes time t to cover a certain distance. Since car A can accelerate at twice the rate, it will take time t/2 to cover the same distance.
To find the total time taken by car B, we add the acceleration time to the constant speed time: t + t/2 = 3t/2.
Therefore, car B takes 3/2 times longer than car A to cover the same distance.
If car A accelerated for twice as long as car B, it would have an acceleration time of 2t. The distance covered during the acceleration phase is given by (1/2)at^2, where a is the acceleration. Since car A accelerates at twice the rate, its acceleration is 2a. So, the distance covered during the acceleration phase by car A is (1/2)(2a)(2t)^2 = 8at^2.
Since car B does not have an acceleration phase, it covers the entire distance at a constant speed. Therefore, the distance covered by car B is simply vt, where v is the constant speed.
Hence, car A would travel 8 times the distance of car B and be traveling at twice the speed.
Learn more about speed from the following link:
https://brainly.com/question/6280317
#SPJ11.
An electron is placed a distance of 10x10-6m from an unknown charge. The electron is released and moves away from the unknown charge (which is held stationary.) By observing the electron, you deduce that 7x10-18J of energy is lost once the electron has arrived at a distance of 8x10-4m from the unknown charge. What is the size and sign of the unknown charge? (Give your answer in x10-14C.)
Answers
The problem describes an electron is placed at a distance of 10x10^-6m from an unknown charge, and the electron moves away from the unknown charge which is held stationary.
The energy lost is given as 7x10^-18 J when the electron reaches a distance of 8x10^-4 m from the unknown charge. The task is to find the size and sign of the unknown charge. Let's begin. The electric potential energy between the electron and the unknown charge initially isUinitial = kq1q2/r1wherek = Coulomb's constant = 9x10^9 Nm^2C^-2q1 = charge of electron = -1.6x10^-19 Cq2 = charge of unknown particle = unknownr1 = initial distance between charges = 10x10^-6 mThe electric potential energy between the electron and the unknown charge when the electron reaches the distance of 8x10^-4m isUfinal = kq1q2/r2where, r2 = 8x10^-4mEnergy lost, ΔU = Ufinal - Uinitial= kq1q2(1/r2 - 1/r1)7x10^-18 = 9x10^9 × -1.6x10^-19 × q2(1/8x10^-4 - 1/10x10^-6)q2 = -5.35 x 10^-14 CThe negative sign for the charge indicates that the unknown charge is a positive charge. Therefore, the size and sign of the unknown charge are 5.35x10^-14C and positive, respectively. Answer: 5.35x10^-14 C, positive charge.
To Learn more about electron Click this!
brainly.com/question/30256231
#SPJ11
44. is performed on through holes to improve hole dimensional accuracy
a. countersink
b. reaming
c. boring
d. counterbore
e. spot facing
Answers
A reaming is used in either a clockwise or counter clockwise rotation. It is commonly used to finish drilled holes to a close tolerance.
Reaming is performed on through holes to improve hole dimensional accuracy. When a hole is drilled, it often has rough and jagged edges, making it hard to fit a bolt or pin in it.
The hole can also be off-center or have a diameter that's too small. This is when reaming comes in to play.A reamer is a tool with multiple cutting edges that can be used to finish holes.
As the reamer rotates, its cutting edges shave off small amounts of metal from the hole, removing any high spots or surface imperfections in the process.
Reaming is typically done after drilling to ensure a precise hole diameter, straightness, and finish. Reaming can be done by hand or by machine.
Reaming is commonly used to finish the holes of engine cylinders, bearings, and other critical components.
The length of the reamer varies based on the length of the hole. The reamer's diameter is between .01 and .06 mm smaller than the size of the hole.
You can rotate a reamer either clockwise or anticlockwise. It is frequently employed to precisely finish drilled holes.
learn more about rotation from given link
https://brainly.com/question/4227499
#SPJ11
What Are The Escape Velocities For The Earth And Sun? Please Write The Answer Neatly.
Answers
Escape Velocity:Escape velocity is the speed an object needs to achieve to escape the gravitational force of a celestial body such as a planet or star.
The amount of force required to escape varies depending on the size and mass of the body in question. The escape velocities for the earth and sun are as follows:Escape velocity for earth:It is the speed needed to break free from Earth's gravitational pull. Earth's gravitational force is about 9.8 m/s² at its surface. The escape velocity of earth is 11.2 km/s (40,320 km/h or 25,020 mph).Escape velocity for sun:The escape velocity of the sun is 618 km/s (2.23 million km/h or 1.38 million mph). The escape velocity is the speed an object must achieve to escape the gravitational pull of the sun. Even though the sun is much larger and more massive than Earth, the escape velocity of the sun is much higher than that of Earth, which is due to its enormous mass. The velocities required to escape the gravitational pull of a planet or star are important to space travel and exploration. The escape velocity is dependent on an object's mass, the mass of the body it is escaping from, and the distance between the object and the center of the body.
To Learn more about Escape Click this!
brainly.com/question/30146588
#SPJ11
Two particles, one with charge −7.13μC and one with charge 1.87μC, are 6.59 cm apart. What is the magnitude of the force that one particle exerts on the other? force: ___________
Answers
The magnitude of the force exerted between two charged particles, one with a charge of -7.13 μC and the other with a charge of 1.87 μC, when they are 6.59 cm apart, can be calculated using Coulomb's Law. The force is determined to be a value obtained by substituting the given charges and distance into the formula, considering the electrostatic constant.
The magnitude of the force between two charged particles can be calculated using Coulomb's Law. According to Coulomb's Law, the magnitude of the force (F) between two charged particles is given by:
F = k * |q1 * q2| / [tex]r^2[/tex]
where k is the electrostatic constant ([tex]k ≈ 8.99 × 10^9 N m^2/C^2[/tex]), q1 and q2 are the charges of the particles, and r is the distance between them.
Plugging in the values given in the problem, we have:
[tex]q1 = -7.13 μC = -7.13 × 10^-6 C\\\\q2 = 1.87 μC = 1.87 × 10^-6 C\\r = 6.59 cm = 6.59 × 10^-2 m[/tex]
Substituting these values into the formula, we get:
F = [tex](8.99 × 10^9 N m^2/C^2) * |-7.13 × 10^-6 C * 1.87 × 10^-6 C| / (6.59 × 10^-2 m)^2[/tex]
Evaluating this expression will give us the magnitude of the force between the two particles.
To know more about Coulomb's Law refer to-
https://brainly.com/question/506926
#SPJ11
A wind gust of 155 mi/hr blows over a roof of a house during a hurricane. What is the total air pressure on the roof? The density of air is 1.29 kg/m3.
Answers
The total air pressure on the roof is 3088.67 Pa.
Let's recalculate the total air pressure on the roof using the correct formula.
To calculate the total air pressure on the roof, we can use the dynamic pressure formula:
Dynamic Pressure = 0.5 * ρ * [tex]v^2[/tex]
where:
q = Dynamic Pressure
ρ (rho) = density of air (1.29 kg/[tex]m^3[/tex])
v = velocity of the wind gust (155 mi/hr)
First, let's convert the wind gust velocity from miles per hour (mi/hr) to meters per second (m/s):
1 mile = 1609.34 meters
1 hour = 3600 seconds
155 mi/hr = (155 * 1609.34) meters / (3600 seconds) ≈ 69.20 m/s
Now we can calculate the dynamic pressure:
q = 0.5 * 1.29 kg/[tex]m^3[/tex] * [tex](69.20 m/s)^2[/tex]
q ≈ 3088.67 Pa (Pascal)
Therefore, the total air pressure on the roof is approximately 3088.67 Pa.
know more about pressure here:
https://brainly.com/question/28012687
#SPJ8
Star A has a magnitude of 4 and Star B has a magnitude of 6. How much brighter is Star A than Star B?
a. 0.0006554
b. 0.16
c. 0.0002621
d. 1.5
e. 3.33
f. 1526
g. 0.0102
h. 2.5
i. 610
j. 97.7
k. 2
l. 0.00164
m. 5
n. 6.25
o. 3815
Answers
The difference in magnitudes between the stars can be found using the formula Δm = m1 - m2. Where m1 = magnitude of star A, m2 = magnitude of star B, and Δm is the difference in magnitudes.
Given that Star A has a magnitude of 4 and Star B has a magnitude of 6. Therefore,Δm = 4 - 6= -2.
The negative sign indicates that star B is brighter than star A.
Thus, to find out how much brighter Star A is than Star B, we need to take the antilogarithm of Δm/2.5.
This can be calculated as follows:antilog (-2/2.5)= antilog (-0.8) = 0.1585.
The antilogarithm is approximately equal to 0.16.
Therefore, Star A is 0.16 times brighter than Star B. Answer: The brightness ratio between Star A and Star B is 0.16.
Learn more about stars here ;
https://brainly.com/question/31987999
#SPJ11
What is the electric fux through the surface when it is at 45∘ to the field? A flat surfaco with area 2.9 m2 is in a uniform Express your answer using two significant figures. electric field of 920 N/C. X Incorrect; Try Again; 22 attempts remaining Part C What is the electric fux through the surtace when it is parallel to the fiald?
Answers
The electric flux through the surface when it is at 45° to the field is 3615 N·m²/C and when it is parallel to the field is 2668 N·m²/C.The electric field is E = 920 N/C.The area of the flat surface is A = 2.9 m².
The electric flux through a surface is given by:Φ = E × A × cosθ where E = electric field, A = area, θ = angle between the area vector and the electric field vector.
At θ = 45°, cosθ = cos(45°) = 1/√2.
Thus, the electric flux is given by:Φ = E × A × cosθ= 920 × 2.9 × (1/√2)= 3615 N·m²/C
When the surface is parallel to the field, then θ = 0° and cosθ = cos(0°) = 1.
So, the electric flux is given by:Φ = E × A × cosθ= 920 × 2.9 × 1= 2668 N·m²/C.
Therefore, the electric flux through the surface when it is at 45° to the field is 3615 N·m²/C and when it is parallel to the field is 2668 N·m²/C.
Learn more about electric field here ;
https://brainly.com/question/11482745
#SPJ11
be driving a nail with a hammer When a hammer with a mass of 5.5kg hits a nail. the hammer stops at a speed of 4.8m/s and stops in about 7.4ms. 1) How much impact does the nail receive? 2) What is the average force acting on a nail?
Answers
1) the impact that the nail receives is -149.856 Joules
2) the average force acting on a nail is 7.43 kN (approx.)
1) The impact that the nail receives can be calculated using the formula for kinetic energy as given below;
Kinetic energy = 0.5 * mass * velocity²
Kinetic energy of the hammer before hitting the nail can be calculated as;
KE1 = 0.5 * m * v²
Where,m = mass of the hammer = 5.5 kgv = velocity of the hammer before hitting the nail = 0 m/s
KE1 = 0.5 * 5.5 * 0² = 0 Joules
Kinetic energy of the hammer after hitting the nail can be calculated as;
KE2 = 0.5 * m * v²
Where,v = velocity of the hammer after hitting the nail = 4.8 m/sKE2 = 0.5 * 5.5 * 4.8² = 149.856 Joules
The impact that the nail receives can be calculated as the difference in kinetic energy before and after hitting the nail.
Impact = KE1 - KE2 = 0 - 149.856 = -149.856 Joules
2) The average force acting on a nail can be calculated using the formula given below;
Average force = (final velocity - initial velocity) / time taken
The time taken by the hammer to stop after hitting the nail is given as 7.4 ms = 0.0074 seconds.
The final velocity of the hammer after hitting the nail is 4.8 m/s
.The initial velocity of the hammer before hitting the nail can be calculated using the formula of motion as given below;v = u + atu = v - at
Where,u = initial velocity of the hammer
a = acceleration of the hammer = F / mu = a * t + (v - u)
F = mu * a
Where,m = mass of the hammer
a = acceleration of the hammer = F / mut = time taken by the hammer to stop after hitting the nail
v = final velocity of the hammer after hitting the nail
u = initial velocity of the hammer before hitting the nail
u = v - a * tu = 4.8 - (F / m) * 0.0074
The average force acting on the nail can be calculated using the above equations.
Average force = (4.8 - (F / m) * 0.0074 - 0) / 0.0074F = (4.8 - u) * m / t
Average force = (4.8 - (4.8 - (F / m) * 0.0074)) * m / 0.0074
Average force = F * 5.5 / 0.0074
Average force = 7432.4324 * F
Average force = 7.43 kN (approx.)
Learn more about kinetic energy at
https://brainly.com/question/15032311
#SPJ11
Use the Luminosity Distance Formula.
Find the luminosity of a star whose apparent brightness is 5.60×10⁻⁹ watt/m², and whose distance is about 6×10¹⁷ meters.
Formula: Absolute Brightness (AB)= Luminosity /4π r²
a. 2.533×10⁻²⁸ watts
b. 3.231×10⁻²⁸ watts
c. 3.231×10²⁸ watts
d. 2.533×10²⁸ watts
Answers
The luminosity of the star is approximately 7.984 × 10²⁶ watts.
To find the luminosity of the star, we can use the luminosity distance formula:
Absolute Brightness (AB) = Luminosity / (4π * r^2)
where AB is the apparent brightness, r is the distance, and Luminosity is the value we need to find.
Rearranging the formula, we get:
Luminosity = AB * (4π * r^2)
Substituting the given values:
AB = 5.60 × 10⁻⁹ watt/m²
r = 6 × 10¹⁷ meters
Luminosity = (5.60 × 10⁻⁹ watt/m²) * (4π * (6 × 10¹⁷ meters)^2)
Luminosity = (5.60 × 10⁻⁹ watt/m²) * (4π * 36 × 10³⁴ meters²)
Luminosity = (5.60 × 4π * 36) × 10³⁴ * 10⁻⁹
Luminosity = (79.84π) × 10²⁵
Now we can calculate the numerical value:
Luminosity ≈ 79.84 × 10²⁵
Luminosity ≈ 7.984 × 10²⁶ watts
Therefore, the luminosity of the star is approximately 7.984 × 10²⁶ watts.
None of the provided options (a, b, c, or d) match this result exactly.
Learn more about luminosity here:
https://brainly.com/question/13945214
#SPJ11
How much energy is required to change a 40.0-g ice cube from ice at -10.0°C to water at 70 °C?
Answers
23712 J of energy is required to change a 40.0-g ice cube from ice at -10.0°C to water at 70 °C. The energy required to melt the ice, which is the latent heat of fusion of ice.
The energy required to change a 40.0-g ice cube from ice at -10.0°C to water at 70 °C is the sum of the following:
The energy required to melt the ice, which is the latent heat of fusion of ice.
The energy required to raise the temperature of the water from 0°C to 70°C, which is the specific heat capacity of water.
The latent heat of fusion of ice is 334 J/g. The specific heat capacity of water is 4.184 J/g°C.
So, the energy required to melt the ice is:
energy = mass * latent heat of fusion = 40.0 g * 334 J/g = 13360 J
The energy required to raise the temperature of the water is:
energy = mass * specific heat capacity * change in temperature = 40.0 g * 4.184 J/g°C * (70°C - 0°C) = 10352 J
Therefore, the total energy required is:
energy = 13360 J + 10352 J = 23712 J
Therefore, 23712 J of energy is required to change a 40.0-g ice cube from ice at -10.0°C to water at 70 °C.
To learn more about latent heat of fusion click here
https://brainly.com/question/30762921
#SPJ11
The sum of two point charges is +15μC. When they are 3.8 cm apart, each experiences a force of 280 N. Find the charges given that the force is: a) repulsive. (List your two answers in increasing order of magnitude) μC，μC a) attractive. (List your two answers in increasing order of magnitude) μC,μC
Answers
The charges when the force is repulsive (in increasing order of magnitude) are 7.28 μC, 7.72 μC. The charges when the force is attractive (in increasing order of magnitude) are 0.28 μC, 14.72 μC.
(i) Repulsive force: F = 280 NQ1 = x μCQ2 = (15 - x) μC(d = distance between the charges)F = (1/4πε₀) (Q₁Q₂/d²) Where,ε₀ = permittivity of free space
= 8.85 × 10⁻¹² N⁻¹m⁻²d = 3.8 cm = 3.8 × 10⁻² m280 = (1/4πε₀) [x(15 - x)]/(3.8 × 10⁻²)π × 8.85 × 10⁻¹² × 3.8 × 10⁻² × 280 = x(15 - x)x² - 15x + 63.4 = 0.
On solving this, we get;x = 7.71 μC (or) x = 7.28 μC.
Therefore, charges are 7.28 μC, 15 - 7.28 = 7.72 μC when the force is repulsive.
(ii) Attractive force:Q1 = x μCQ2 = (15 - x) μCF = -280 N280 = (1/4πε₀) [x(15 - x)]/(3.8 × 10⁻²)π × 8.85 × 10⁻¹² × 3.8 × 10⁻² × (-280) = x(15 - x)x² - 15x - 63.4 = 0.
On solving this, we get;x = 0.28 μC (or) x = 14.7 μC.
Therefore, charges are 0.28 μC, 15 - 0.28 = 14.72 μC when the force is attractive.
The charges when the force is repulsive (in increasing order of magnitude) are 7.28 μC, 7.72 μC.The charges when the force is attractive (in increasing order of magnitude) are 0.28 μC, 14.72 μC.
Learn more about charges here ;
https://brainly.com/question/13871705
#SPJ11
Two 1.20 mm nonconducting rods meet at a right angle. One rod carries +1.70 μC of charge distributed uniformly along its length, and the other carries -1.70 μC distributed uniformly along it (Figure 1).
Find the magnitude of the electric field these rods produce at point PP, which is 60.0 cm from each rod. Express your answer with the appropriate units.
Find the direction angle of the electric field from part A. The angle is measured from the +x-axis toward the +y-axis. Express your answer in degrees.
Answers
To find the direction angle of the electric field, we can use trigonometry. Since the rods meet at a right angle, the direction angle will be 45 degrees.
To find the magnitude of the electric field produced by the rods at point P, we can use the principle of superposition. The electric field at P due to each rod can be calculated separately and then summed.
Considering each rod individually, we can use the equation for the electric field produced by a uniformly charged rod at a point on its perpendicular bisector:
Electric field (E1) produced by the positive rod = (k * Q1) / [tex](L1 * sqrt((L1/2)^2 + d^2))[/tex]
Electric field (E2) produced by the negative rod = (k * Q2) / (L2 * sqrt[tex]((L2/2)^2 + d^2))[/tex]
where k is the Coulomb's constant, Q1 and Q2 are the charges on the rods, L1 and L2 are the lengths of the rods, and d is the distance from the midpoint of each rod to point P.
Since the rods are nonconducting and have opposite charges, the magnitudes of their charges are equal: |Q1| = |Q2| = 1.70 μC.
Substituting the given values, the equation becomes:
Electric field (E1) = [tex](9 * 10^9 N*m^2/C^2 * 1.70 * 10^-6 C) / (1.20 * 10^-3 m * sqrt((1.20 * 10^-3 m/2)^2 + (0.60 m)^2))[/tex]
Electric field (E2) = [tex](9 * 10^9 N*m^2/C^2 * 1.70 * 10^-6 C) / (1.20 * 10^-3 m * sqrt((1.20 * 10^-3 m/2)^2 + (0.60 m)^2))[/tex]
Calculate these expressions to find the electric fields (E1 and E2) produced by the rods. Then, add the magnitudes of these electric fields to obtain the total electric field at point P.
To know more about electric field refer to-
https://brainly.com/question/11482745
#SPJ11
Explain how Cavendish was able to determine the force of attraction in his experimental apparatus.
Answers
Cavendish used a torsion balance to measure the tiny twisting motion caused by gravitational attraction.
Henry Cavendish, an English scientist, devised an ingenious experiment in the late 18th century to determine the force of attraction between two masses, which is now known as the Cavendish experiment. His apparatus consisted of a horizontal torsion balance, two small lead spheres, and two larger lead spheres.
Cavendish suspended the horizontal torsion balance from a thin wire, with two smaller lead spheres attached to either end. The larger lead spheres were positioned near the smaller spheres but did not touch them. The balance was enclosed in a chamber to minimize external influences.
Cavendish's ingenious method involved measuring the tiny twisting motion of the torsion balance caused by the gravitational attraction between the large and small spheres. The gravitational force between the spheres would induce a small torque on the balance, causing it to rotate slightly.
By carefully observing the angle of rotation of the torsion balance, Cavendish could infer the magnitude of the gravitational force. This was achieved by comparing the observed deflection to the known torsional constant of the wire, which related the angle of rotation to the torque applied.
The key to Cavendish's experiment was the sensitivity of the torsion balance and his ability to measure tiny angular deflections. He used a telescope to observe the movements of a small mirror attached to the balance, allowing him to detect even minute changes in its position.
By conducting repeated measurements and applying precise mathematical calculations, Cavendish was able to determine the force of attraction between the masses. His groundbreaking experiment provided the first accurate measurement of the gravitational constant, an essential parameter in understanding the fundamental forces of nature.
learn more about Cavendish Experiment.
brainly.com/question/29331473
#SPJ11
